How many gram of CaI₂ are needed to completely precipitate the Ag⁺ ions as AgI from 75.0 mL solution of 0.300 M AgNO₃ according to the balanced chemical reaction: 2 AgNO₃(aq) + CaI₂(aq) → 2 AgI(s) + Ca(NO₃)₂(aq)
How do i start the conversions to get the answers