Which statement explains why △ABC is congruent to △A′B′C′?


You can map △ABC onto △A′B′C′ by translating it 2 units up and reflecting it across the y-axis, which is a sequence of rigid motions.

You can map △ABC onto △A′B′C′ reflecting it across the line y = x and rotating it 90° counterclockwise about the origin, which is a sequence of rigid motions.

You can map △ABC onto △A′B′C′ by reflecting it across the x-axis and then across the y-axis, which is a sequence of rigid motions.

You can map △ABC onto △A′B′C′ by translating it 6 units left and reflecting it over the x-axis, which is a sequence of rigid motions.