Select the correct answer torm eacn arop-down menu.
Given: m/AOB = 42°
m/EOF= 66°
Prove: m/COD = 72°
A
B
m
E
Complete the proof.
It is given that m/AOB
m/BOC 66°. By the
m/AOC + m/COD = 180°. After application of the
42° and m/EOF 66°. By the
m/AOC
108, and by the
ZEOF ZBOC. Therefore,
m/COD= 72°.

Select the correct answer torm eacn aropdown menu Given mAOB 42 mEOF 66 Prove mCOD 72 A B m E Complete the proof It is given that mAOB mBOC 66 By the mAOC mCOD class=

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