Lead(Il) bromide is prepared using the following reaction:
Рb(NO3)2(aq) + KBr(aq) --> PbBr2(s) + KNO3(aq) (unbalanced)
How many milliliters of 1.25 M Lead(II) nitrate (Pb(NO3)2) are needed to prepare 150 grams of PbBr2 in excess potassium bromide solution. Assume you have 100% yield.
a) Fill in the stoichiometric flowchart below with the information from this problem.
b) Show the dimensional analysis calculation required o calculate the Millileters of 1.25M Lead (II) nitrate needed .