Question 31 point)
The equation
2²=25 will have how many solutions for x?
One solution: x 25/2 since the inverse operation is to divide
One solution: x-5 since5/2=25
Two solutions x-5andx-5ance 52-25 and also (5/2-25 and x2 equations always have 2 solutions
Two solutions x 25/2 andx=-25/2 since 2 equations always have 2 solutions

Question 31 point The equation 225 will have how many solutions for x One solution x 252 since the inverse operation is to divide One solution x5 since5225 Two class=
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